(2x-4)(2x+4)+12=0

Solution for (2x-4)(2x+4)+12=0 equation:

Simplifying
(2x + -4)(2x + 4) + 12 = 0

Reorder the terms:
(-4 + 2x)(2x + 4) + 12 = 0

Reorder the terms:
(-4 + 2x)(4 + 2x) + 12 = 0

Multiply (-4 + 2x) * (4 + 2x)
(-4(4 + 2x) + 2x * (4 + 2x)) + 12 = 0
((4 * -4 + 2x * -4) + 2x * (4 + 2x)) + 12 = 0
((-16 + -8x) + 2x * (4 + 2x)) + 12 = 0
(-16 + -8x + (4 * 2x + 2x * 2x)) + 12 = 0
(-16 + -8x + (8x + 4x2)) + 12 = 0

Combine like terms: -8x + 8x = 0
(-16 + 0 + 4x2) + 12 = 0
(-16 + 4x2) + 12 = 0

Reorder the terms:
-16 + 12 + 4x2 = 0

Combine like terms: -16 + 12 = -4
-4 + 4x2 = 0

Solving
-4 + 4x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + 4x2 = 0 + 4

Combine like terms: -4 + 4 = 0
0 + 4x2 = 0 + 4
4x2 = 0 + 4

Combine like terms: 0 + 4 = 4
4x2 = 4

Divide each side by '4'.
x2 = 1

Simplifying
x2 = 1

Take the square root of each side:
x = {-1, 1}