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(2x-4)(3x-4)=114
We move all terms to the left:
(2x-4)(3x-4)-(114)=0
We multiply parentheses ..
(+6x^2-8x-12x+16)-114=0
We get rid of parentheses
6x^2-8x-12x+16-114=0
We add all the numbers together, and all the variables
6x^2-20x-98=0
a = 6; b = -20; c = -98;
Δ = b2-4ac
Δ = -202-4·6·(-98)
Δ = 2752
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2752}=\sqrt{64*43}=\sqrt{64}*\sqrt{43}=8\sqrt{43}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-8\sqrt{43}}{2*6}=\frac{20-8\sqrt{43}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+8\sqrt{43}}{2*6}=\frac{20+8\sqrt{43}}{12} $
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