(2x-4)(5x+3)=-17

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Solution for (2x-4)(5x+3)=-17 equation: 



(2x-4)(5x+3)=-17

We move all terms to the left:

(2x-4)(5x+3)-(-17)=0

We add all the numbers together, and all the variables

(2x-4)(5x+3)+17=0

We multiply parentheses ..

(+10x^2+6x-20x-12)+17=0

We get rid of parentheses

10x^2+6x-20x-12+17=0

We add all the numbers together, and all the variables

10x^2-14x+5=0

a = 10; b = -14; c = +5;
Δ = b2-4ac
Δ = -142-4·10·5
Δ = -4
Delta is less than zero, so there is no solution for the equation

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