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(2x-4)(5x-5)=0
We multiply parentheses ..
(+10x^2-10x-20x+20)=0
We get rid of parentheses
10x^2-10x-20x+20=0
We add all the numbers together, and all the variables
10x^2-30x+20=0
a = 10; b = -30; c = +20;
Δ = b2-4ac
Δ = -302-4·10·20
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-10}{2*10}=\frac{20}{20} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+10}{2*10}=\frac{40}{20} =2 $
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