(2x-4)(6x+6=0)

Solution for (2x-4)(6x+6=0) equation:

(2x-4)(6x+6=0)

We move all terms to the left:

(2x-4)(6x+6-(0))=0

We add all the numbers together, and all the variables

(2x-4)(6x+6)=0

We multiply parentheses ..

(+12x^2+12x-24x-24)=0

We get rid of parentheses

12x^2+12x-24x-24=0

We add all the numbers together, and all the variables

12x^2-12x-24=0

a = 12; b = -12; c = -24;
Δ = b2-4ac
Δ = -122-4·12·(-24)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-36}{2*12}=\frac{-24}{24}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+36}{2*12}=\frac{48}{24}
=2
$