(2x-4)(6x-12)=0

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Solution for (2x-4)(6x-12)=0 equation: 



(2x-4)(6x-12)=0

We multiply parentheses ..

(+12x^2-24x-24x+48)=0

We get rid of parentheses

12x^2-24x-24x+48=0

We add all the numbers together, and all the variables

12x^2-48x+48=0

a = 12; b = -48; c = +48;
Δ = b2-4ac
Δ = -482-4·12·48
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{48}{24}=2$

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