(2x-4)(x+12)=0

Solution for (2x-4)(x+12)=0 equation:

(2x-4)(x+12)=0

We multiply parentheses ..

(+2x^2+24x-4x-48)=0

We get rid of parentheses

2x^2+24x-4x-48=0

We add all the numbers together, and all the variables

2x^2+20x-48=0

a = 2; b = 20; c = -48;
Δ = b2-4ac
Δ = 202-4·2·(-48)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-28}{2*2}=\frac{-48}{4}
=-12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+28}{2*2}=\frac{8}{4}
=2
$