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(2x-4)(x-2)(2)=484
We move all terms to the left:
(2x-4)(x-2)(2)-(484)=0
We multiply parentheses ..
(+2x^2-4x-4x+8)2-484=0
We multiply parentheses
4x^2-8x-8x+16-484=0
We add all the numbers together, and all the variables
4x^2-16x-468=0
a = 4; b = -16; c = -468;
Δ = b2-4ac
Δ = -162-4·4·(-468)
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7744}=88$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-88}{2*4}=\frac{-72}{8} =-9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+88}{2*4}=\frac{104}{8} =13 $
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