(2x-4)(x-2)=(2x-4)(x-3)

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Solution for (2x-4)(x-2)=(2x-4)(x-3) equation: 



(2x-4)(x-2)=(2x-4)(x-3)

We move all terms to the left:

(2x-4)(x-2)-((2x-4)(x-3))=0

We multiply parentheses ..

(+2x^2-4x-4x+8)-((2x-4)(x-3))=0



We calculate terms in parentheses: -((2x-4)(x-3)), so:

(2x-4)(x-3)

We multiply parentheses ..

(+2x^2-6x-4x+12)

We get rid of parentheses

2x^2-6x-4x+12

We add all the numbers together, and all the variables

2x^2-10x+12

Back to the equation:

-(2x^2-10x+12)



We get rid of parentheses

2x^2-2x^2-4x-4x+10x+8-12=0

We add all the numbers together, and all the variables

2x-4=0

We move all terms containing x to the left, all other terms to the right

2x=4

x=4/2

x=2

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