(2x-4)+(2x-4)+(x+6)+(x+6)=0

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Solution for (2x-4)+(2x-4)+(x+6)+(x+6)=0 equation: 



(2x-4)+(2x-4)+(x+6)+(x+6)=0

We get rid of parentheses

2x+2x+x+x-4-4+6+6=0

We add all the numbers together, and all the variables

6x+4=0

We move all terms containing x to the left, all other terms to the right

6x=-4

x=-4/6

x=-2/3

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