If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(2x-4)+(x+3)=x-2
We move all terms to the left:
(2x-4)+(x+3)-(x-2)=0
We get rid of parentheses
2x+x-x-4+3+2=0
We add all the numbers together, and all the variables
2x+1=0
We move all terms containing x to the left, all other terms to the right
2x=-1
x=-1/2
x=-1/2
| 2/5-m=9/3m-6 | | 3x-1+7x+21=180 | | 7*(-45+y)=-5 | | 2(x+8)=38 | | 31-7x=13+11x | | 3x^2+8=83 | | 10/6=n/10 | | x+73+63+x+54=180 | | 5(a+4)=6a+1=12 | | 22s^2-748s-7392=0 | | 9x+17=4x-48 | | (-45+y)*7=-5 | | 6(2-3u)=48 | | 4(-2x-3)=-12 | | 6x+12=2/3(6x=6) | | 22x^2+748x+7392=0 | | −x=9(x−10) | | -4=x/4+6 | | 22s^2+748s+7392=0 | | 3(2x+4=-12 | | 14c-12c=12 | | 9^0.4x=5 | | 4x-34/3=3x | | 8(5-12a)=-152 | | 5(5x+10)=425 | | y-2=4/9(х+6) | | 8x+14-2x=50 | | Y=3x2+5x-2 | | 2=3n-13 | | N(t)=4t^2+7t-2 | | 5x+-4=16 | | n^2+2=18 |