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(2x-4)+x+(x/2)=126
We move all terms to the left:
(2x-4)+x+(x/2)-(126)=0
We add all the numbers together, and all the variables
(2x-4)+x+(+x/2)-126=0
We add all the numbers together, and all the variables
x+(2x-4)+(+x/2)-126=0
We get rid of parentheses
x+2x+x/2-4-126=0
We multiply all the terms by the denominator
x*2+2x*2+x-4*2-126*2=0
We add all the numbers together, and all the variables
x+x*2+2x*2-260=0
Wy multiply elements
x+2x+4x-260=0
We add all the numbers together, and all the variables
7x-260=0
We move all terms containing x to the left, all other terms to the right
7x=260
x=260/7
x=37+1/7
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