(2x-4)-8x=(6x+12)

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Solution for (2x-4)-8x=(6x+12) equation: 



(2x-4)-8x=(6x+12)

We move all terms to the left:

(2x-4)-8x-((6x+12))=0

We add all the numbers together, and all the variables

-8x+(2x-4)-((6x+12))=0

We get rid of parentheses

-8x+2x-((6x+12))-4=0



We calculate terms in parentheses: -((6x+12)), so:

(6x+12)

We get rid of parentheses

6x+12

Back to the equation:

-(6x+12)



We add all the numbers together, and all the variables

-6x-(6x+12)-4=0

We get rid of parentheses

-6x-6x-12-4=0

We add all the numbers together, and all the variables

-12x-16=0

We move all terms containing x to the left, all other terms to the right

-12x=16

x=16/-12

x=-1+1/3

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