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(2x-4)/(5x-10)=0
Domain of the equation: (5x-10)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
5x!=10
x!=10/5
x!=2
x∈R
(2x-4)=0
We get rid of parentheses
2x-4=0
We move all terms containing x to the left, all other terms to the right
2x=4
x=4/2
x=2
Równanie nie ma rozwiązania
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