(2x-4)/(7)=(2-2x)/(4)

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Solution for (2x-4)/(7)=(2-2x)/(4) equation: 



(2x-4)/(7)=(2-2x)/(4)

We move all terms to the left:

(2x-4)/(7)-((2-2x)/(4))=0

We add all the numbers together, and all the variables

(2x-4)/7-((-2x+2)/4)=0

We calculate fractions


2x/()+(-((-2x+2)*7)/()=0



We calculate terms in parentheses: +(-((-2x+2)*7)/(), so:

-((-2x+2)*7)/(

We multiply all the terms by the denominator


-((-2x+2)*7)



We calculate terms in parentheses: -((-2x+2)*7), so:

(-2x+2)*7

We multiply parentheses

-14x+14

Back to the equation:

-(-14x+14)



We get rid of parentheses

14x-14

Back to the equation:

+(14x-14)



We get rid of parentheses

2x/()+14x-14=0

We multiply all the terms by the denominator


2x+14x*()-14*()=0

We add all the numbers together, and all the variables

2x+14x*()=0

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