(2x-4)/10=(7x+16)/5

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Solution for (2x-4)/10=(7x+16)/5 equation: 



(2x-4)/10=(7x+16)/5

We move all terms to the left:

(2x-4)/10-((7x+16)/5)=0

We calculate fractions


2x/()+(-((7x+16)*10)/()=0



We calculate terms in parentheses: +(-((7x+16)*10)/(), so:

-((7x+16)*10)/(

We multiply all the terms by the denominator


-((7x+16)*10)



We calculate terms in parentheses: -((7x+16)*10), so:

(7x+16)*10

We multiply parentheses

70x+160

Back to the equation:

-(70x+160)



We get rid of parentheses

-70x-160

Back to the equation:

+(-70x-160)



We get rid of parentheses

2x/()-70x-160=0

We multiply all the terms by the denominator


2x-70x*()-160*()=0

We add all the numbers together, and all the variables

2x-70x*()=0

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