(2x-4)=(5x-17)+(x+4)

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Solution for (2x-4)=(5x-17)+(x+4) equation: 



(2x-4)=(5x-17)+(x+4)

We move all terms to the left:

(2x-4)-((5x-17)+(x+4))=0

We get rid of parentheses

2x-((5x-17)+(x+4))-4=0



We calculate terms in parentheses: -((5x-17)+(x+4)), so:

(5x-17)+(x+4)

We get rid of parentheses

5x+x-17+4

We add all the numbers together, and all the variables

6x-13

Back to the equation:

-(6x-13)



We get rid of parentheses

2x-6x+13-4=0

We add all the numbers together, and all the variables

-4x+9=0

We move all terms containing x to the left, all other terms to the right

-4x=-9

x=-9/-4

x=2+1/4

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