(2x-4)=(6x-10)=(2x+16)

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Solution for (2x-4)=(6x-10)=(2x+16) equation: 



(2x-4)=(6x-10)=(2x+16)

We move all terms to the left:

(2x-4)-((6x-10))=0

We get rid of parentheses

2x-((6x-10))-4=0



We calculate terms in parentheses: -((6x-10)), so:

(6x-10)

We get rid of parentheses

6x-10

Back to the equation:

-(6x-10)



We get rid of parentheses

2x-6x+10-4=0

We add all the numbers together, and all the variables

-4x+6=0

We move all terms containing x to the left, all other terms to the right

-4x=-6

x=-6/-4

x=1+1/2

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