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(2x-5)(2x+4)=0
We multiply parentheses ..
(+4x^2+8x-10x-20)=0
We get rid of parentheses
4x^2+8x-10x-20=0
We add all the numbers together, and all the variables
4x^2-2x-20=0
a = 4; b = -2; c = -20;
Δ = b2-4ac
Δ = -22-4·4·(-20)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-18}{2*4}=\frac{-16}{8} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+18}{2*4}=\frac{20}{8} =2+1/2 $
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