(2x-5)(2x+5)=4x(x-4)

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Solution for (2x-5)(2x+5)=4x(x-4) equation: 



(2x-5)(2x+5)=4x(x-4)

We move all terms to the left:

(2x-5)(2x+5)-(4x(x-4))=0

We use the square of the difference formula

4x^2-(4x(x-4))-25=0



We calculate terms in parentheses: -(4x(x-4)), so:

4x(x-4)

We multiply parentheses

4x^2-16x

Back to the equation:

-(4x^2-16x)



We get rid of parentheses

4x^2-4x^2+16x-25=0

We add all the numbers together, and all the variables

16x-25=0

We move all terms containing x to the left, all other terms to the right

16x=25

x=25/16

x=1+9/16

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