(2x-5)(2x-5)=4x(x-4)

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Solution for (2x-5)(2x-5)=4x(x-4) equation: 



(2x-5)(2x-5)=4x(x-4)

We move all terms to the left:

(2x-5)(2x-5)-(4x(x-4))=0

We multiply parentheses ..

(+4x^2-10x-10x+25)-(4x(x-4))=0



We calculate terms in parentheses: -(4x(x-4)), so:

4x(x-4)

We multiply parentheses

4x^2-16x

Back to the equation:

-(4x^2-16x)



We get rid of parentheses

4x^2-4x^2-10x-10x+16x+25=0

We add all the numbers together, and all the variables

-4x+25=0

We move all terms containing x to the left, all other terms to the right

-4x=-25

x=-25/-4

x=6+1/4

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