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(2x-5)(3x+10)=180
We move all terms to the left:
(2x-5)(3x+10)-(180)=0
We multiply parentheses ..
(+6x^2+20x-15x-50)-180=0
We get rid of parentheses
6x^2+20x-15x-50-180=0
We add all the numbers together, and all the variables
6x^2+5x-230=0
a = 6; b = 5; c = -230;
Δ = b2-4ac
Δ = 52-4·6·(-230)
Δ = 5545
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{5545}}{2*6}=\frac{-5-\sqrt{5545}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{5545}}{2*6}=\frac{-5+\sqrt{5545}}{12} $
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