(2x-5)(3x+2)=6x2-10

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Solution for (2x-5)(3x+2)=6x2-10 equation: 



(2x-5)(3x+2)=6x^2-10

We move all terms to the left:

(2x-5)(3x+2)-(6x^2-10)=0

We get rid of parentheses

-6x^2+(2x-5)(3x+2)+10=0

We multiply parentheses ..

-6x^2+(+6x^2+4x-15x-10)+10=0

We get rid of parentheses

-6x^2+6x^2+4x-15x-10+10=0

We add all the numbers together, and all the variables

-11x=0

x=0/-11

x=0

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