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(2x-5)(3x+5)=-60
We move all terms to the left:
(2x-5)(3x+5)-(-60)=0
We add all the numbers together, and all the variables
(2x-5)(3x+5)+60=0
We multiply parentheses ..
(+6x^2+10x-15x-25)+60=0
We get rid of parentheses
6x^2+10x-15x-25+60=0
We add all the numbers together, and all the variables
6x^2-5x+35=0
a = 6; b = -5; c = +35;
Δ = b2-4ac
Δ = -52-4·6·35
Δ = -815
Delta is less than zero, so there is no solution for the equation
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