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D( x )
x+1 = 0
x+1 = 0
x+1 = 0
x+1 = 0 // - 1
x = -1
x in (-oo:-1) U (-1:+oo)
((2*x-5)*(5*x+2))/(x+1) = 0
( 2*x-5 )
2*x-5 = 0 // + 5
2*x = 5 // : 2
x = 5/2
( 5*x+2 )
5*x+2 = 0 // - 2
5*x = -2 // : 5
x = -2/5
x in { 5/2, -2/5 }
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