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(2x-5)(5x+32)=0
We multiply parentheses ..
(+10x^2+64x-25x-160)=0
We get rid of parentheses
10x^2+64x-25x-160=0
We add all the numbers together, and all the variables
10x^2+39x-160=0
a = 10; b = 39; c = -160;
Δ = b2-4ac
Δ = 392-4·10·(-160)
Δ = 7921
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7921}=89$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(39)-89}{2*10}=\frac{-128}{20} =-6+2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(39)+89}{2*10}=\frac{50}{20} =2+1/2 $
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