(2x-5)(x)=1032

Solution for (2x-5)(x)=1032 equation:

(2x-5)(x)=1032

We move all terms to the left:

(2x-5)(x)-(1032)=0

We multiply parentheses

2x^2-5x-1032=0

a = 2; b = -5; c = -1032;
Δ = b2-4ac
Δ = -52-4·2·(-1032)
Δ = 8281
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8281}=91$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-91}{2*2}=\frac{-86}{4}
=-21+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+91}{2*2}=\frac{96}{4}
=24
$