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(2x-5)(x-1)=-12x
We move all terms to the left:
(2x-5)(x-1)-(-12x)=0
We get rid of parentheses
(2x-5)(x-1)+12x=0
We multiply parentheses ..
(+2x^2-2x-5x+5)+12x=0
We get rid of parentheses
2x^2-2x-5x+12x+5=0
We add all the numbers together, and all the variables
2x^2+5x+5=0
a = 2; b = 5; c = +5;
Δ = b2-4ac
Δ = 52-4·2·5
Δ = -15
Delta is less than zero, so there is no solution for the equation
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