(2x-5)*(x-5)=95

Solution for (2x-5)*(x-5)=95 equation:

(2x-5)(x-5)=95

We move all terms to the left:

(2x-5)(x-5)-(95)=0

We multiply parentheses ..

(+2x^2-10x-5x+25)-95=0

We get rid of parentheses

2x^2-10x-5x+25-95=0

We add all the numbers together, and all the variables

2x^2-15x-70=0

a = 2; b = -15; c = -70;
Δ = b2-4ac
Δ = -152-4·2·(-70)
Δ = 785
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{785}}{2*2}=\frac{15-\sqrt{785}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{785}}{2*2}=\frac{15+\sqrt{785}}{4}
$