(2x-5)+(3x-1)/(3x+1)-(x-1)=2

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Solution for (2x-5)+(3x-1)/(3x+1)-(x-1)=2 equation:



(2x-5)+(3x-1)/(3x+1)-(x-1)=2
We move all terms to the left:
(2x-5)+(3x-1)/(3x+1)-(x-1)-(2)=0
Domain of the equation: (3x+1)!=0
We move all terms containing x to the left, all other terms to the right
3x!=-1
x!=-1/3
x!=-1/3
x∈R
We get rid of parentheses
2x+(3x-1)/(3x+1)-x-5+1-2=0
We multiply all the terms by the denominator
2x*(3x+1)+(3x-1)-x*(3x+1)-5*(3x+1)+1*(3x+1)-2*(3x+1)=0
We multiply parentheses
6x^2-3x^2+2x+(3x-1)-x-15x+1*(3x+1)-6x-5-2=0
We get rid of parentheses
6x^2-3x^2+2x+3x-x-15x+1*(3x+1)-6x-1-5-2=0
We add all the numbers together, and all the variables
3x^2-17x+1*(3x+1)-8=0
We move all terms containing x to the left, all other terms to the right
3x^2-17x+1*(3x+1)=8

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