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(2x-5)+(x-3)+x=180
We move all terms to the left:
(2x-5)+(x-3)+x-(180)=0
We add all the numbers together, and all the variables
x+(2x-5)+(x-3)-180=0
We get rid of parentheses
x+2x+x-5-3-180=0
We add all the numbers together, and all the variables
4x-188=0
We move all terms containing x to the left, all other terms to the right
4x=188
x=188/4
x=47
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