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(2x-5)+3x=(-5+2x)+3x
We move all terms to the left:
(2x-5)+3x-((-5+2x)+3x)=0
We add all the numbers together, and all the variables
(2x-5)+3x-((2x-5)+3x)=0
We add all the numbers together, and all the variables
3x+(2x-5)-((2x-5)+3x)=0
We get rid of parentheses
3x+2x-((2x-5)+3x)-5=0
We calculate terms in parentheses: -((2x-5)+3x), so:We add all the numbers together, and all the variables
(2x-5)+3x
We add all the numbers together, and all the variables
3x+(2x-5)
We get rid of parentheses
3x+2x-5
We add all the numbers together, and all the variables
5x-5
Back to the equation:
-(5x-5)
5x-(5x-5)-5=0
We get rid of parentheses
5x-5x+5-5=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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