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(2x-5)/(2x+5)=5/6
We move all terms to the left:
(2x-5)/(2x+5)-(5/6)=0
Domain of the equation: (2x+5)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
2x!=-5
x!=-5/2
x!=-2+1/2
x∈R
(2x-5)/(2x+5)-(+5/6)=0
We get rid of parentheses
(2x-5)/(2x+5)-5/6=0
We calculate fractions
(12x-30)/(12x+30)+(-10x-25)/(12x+30)=0
We multiply all the terms by the denominator
(12x-30)+(-10x-25)=0
We get rid of parentheses
12x-10x-30-25=0
We add all the numbers together, and all the variables
2x-55=0
We move all terms containing x to the left, all other terms to the right
2x=55
x=55/2
x=27+1/2
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