(2x-5)/(3x+2)=(2x-1)/(3x-1)

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Solution for (2x-5)/(3x+2)=(2x-1)/(3x-1) equation: 



(2x-5)/(3x+2)=(2x-1)/(3x-1)

We move all terms to the left:

(2x-5)/(3x+2)-((2x-1)/(3x-1))=0



Domain of the equation: (3x+2)!=0

We move all terms containing x to the left, all other terms to the right

3x!=-2

x!=-2/3

x!=-2/3

x∈R





Domain of the equation: (3x-1))!=0

x∈R



We calculate fractions


((2x-5)*(3x-1)))/((3x+2)*(3x-1)))+(-((2x-1)*(3x+2))/((3x+2)*(3x-1)))=0



We calculate terms in parentheses: +((2x-5)*(3x-1)))/((3x+2)*(3x-1)))+(-((2x-1)*(3x+2))/((3x+2)*(3x-1))), so:

(2x-5)*(3x-1)))/((3x+2)*(3x-1)))+(-((2x-1)*(3x+2))/((3x+2)*(3x-1))

We add all the numbers together, and all the variables

(2x-5)*(3x-1)))/((3x+2)*(3x-1)))+(-((2x-1)*(3x+2))/((3x+2)*(3x

We multiply all the terms by the denominator


(2x-5)*(3x-1)))+2*3x*((3x-1))+(-(2x*((3x-1*3x*((3x+2))+2*3x*((3x

Back to the equation:

+((2x-5)*(3x-1)))+2*3x*((3x-1))+(-(2x*((3x-1*3x*((3x+2))+2*3x*((3x)

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