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(2x-5)/(4x+1)=6
We move all terms to the left:
(2x-5)/(4x+1)-(6)=0
Domain of the equation: (4x+1)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
4x!=-1
x!=-1/4
x!=-1/4
x∈R
(2x-5)-6*(4x+1)=0
We multiply parentheses
(2x-5)-24x-6=0
We get rid of parentheses
2x-24x-5-6=0
We add all the numbers together, and all the variables
-22x-11=0
We move all terms containing x to the left, all other terms to the right
-22x=11
x=11/-22
x=-1/2
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