(2x-5)/2=(3x-1)/4

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Solution for (2x-5)/2=(3x-1)/4 equation: 



(2x-5)/2=(3x-1)/4

We move all terms to the left:

(2x-5)/2-((3x-1)/4)=0

We calculate fractions


2x/()+(-((3x-1)*2)/()=0



We calculate terms in parentheses: +(-((3x-1)*2)/(), so:

-((3x-1)*2)/(

We multiply all the terms by the denominator


-((3x-1)*2)



We calculate terms in parentheses: -((3x-1)*2), so:

(3x-1)*2

We multiply parentheses

6x-2

Back to the equation:

-(6x-2)



We get rid of parentheses

-6x+2

Back to the equation:

+(-6x+2)



We get rid of parentheses

2x/()-6x+2=0

We multiply all the terms by the denominator


2x-6x*()+2*()=0

We add all the numbers together, and all the variables

2x-6x*()=0

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