(2x-5)/3=(3x+1)/2

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Solution for (2x-5)/3=(3x+1)/2 equation: 



(2x-5)/3=(3x+1)/2

We move all terms to the left:

(2x-5)/3-((3x+1)/2)=0

We calculate fractions


2x/()+(-((3x+1)*3)/()=0



We calculate terms in parentheses: +(-((3x+1)*3)/(), so:

-((3x+1)*3)/(

We multiply all the terms by the denominator


-((3x+1)*3)



We calculate terms in parentheses: -((3x+1)*3), so:

(3x+1)*3

We multiply parentheses

9x+3

Back to the equation:

-(9x+3)



We get rid of parentheses

-9x-3

Back to the equation:

+(-9x-3)



We get rid of parentheses

2x/()-9x-3=0

We multiply all the terms by the denominator


2x-9x*()-3*()=0

We add all the numbers together, and all the variables

2x-9x*()=0

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