(2x-5)/4=(8x-3)/12

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Solution for (2x-5)/4=(8x-3)/12 equation: 



(2x-5)/4=(8x-3)/12

We move all terms to the left:

(2x-5)/4-((8x-3)/12)=0

We calculate fractions


2x/()+(-((8x-3)*4)/()=0



We calculate terms in parentheses: +(-((8x-3)*4)/(), so:

-((8x-3)*4)/(

We multiply all the terms by the denominator


-((8x-3)*4)



We calculate terms in parentheses: -((8x-3)*4), so:

(8x-3)*4

We multiply parentheses

32x-12

Back to the equation:

-(32x-12)



We get rid of parentheses

-32x+12

Back to the equation:

+(-32x+12)



We get rid of parentheses

2x/()-32x+12=0

We multiply all the terms by the denominator


2x-32x*()+12*()=0

We add all the numbers together, and all the variables

2x-32x*()=0

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