(2x-5)/4=(x+5)/5

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Solution for (2x-5)/4=(x+5)/5 equation: 



(2x-5)/4=(x+5)/5

We move all terms to the left:

(2x-5)/4-((x+5)/5)=0

We calculate fractions


2x/()+(-((x+5)*4)/()=0



We calculate terms in parentheses: +(-((x+5)*4)/(), so:

-((x+5)*4)/(

We multiply all the terms by the denominator


-((x+5)*4)



We calculate terms in parentheses: -((x+5)*4), so:

(x+5)*4

We multiply parentheses

4x+20

Back to the equation:

-(4x+20)



We get rid of parentheses

-4x-20

Back to the equation:

+(-4x-20)



We get rid of parentheses

2x/()-4x-20=0

We multiply all the terms by the denominator


2x-4x*()-20*()=0

We add all the numbers together, and all the variables

2x-4x*()=0

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