(2x-5)/7=9x+4

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Solution for (2x-5)/7=9x+4 equation:



(2x-5)/7=9x+4
We move all terms to the left:
(2x-5)/7-(9x+4)=0
We get rid of parentheses
(2x-5)/7-9x-4=0
We multiply all the terms by the denominator
(2x-5)-9x*7-4*7=0
We add all the numbers together, and all the variables
(2x-5)-9x*7-28=0
Wy multiply elements
(2x-5)-63x-28=0
We get rid of parentheses
2x-63x-5-28=0
We add all the numbers together, and all the variables
-61x-33=0
We move all terms containing x to the left, all other terms to the right
-61x=33
x=33/-61
x=-33/61

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