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(2x-5)=4x-2(x+5)
We move all terms to the left:
(2x-5)-(4x-2(x+5))=0
We get rid of parentheses
2x-(4x-2(x+5))-5=0
We calculate terms in parentheses: -(4x-2(x+5)), so:We get rid of parentheses
4x-2(x+5)
We multiply parentheses
4x-2x-10
We add all the numbers together, and all the variables
2x-10
Back to the equation:
-(2x-10)
2x-2x+10-5=0
We add all the numbers together, and all the variables
5!=0
There is no solution for this equation
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