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(2x-6)(2x-6)=98
We move all terms to the left:
(2x-6)(2x-6)-(98)=0
We multiply parentheses ..
(+4x^2-12x-12x+36)-98=0
We get rid of parentheses
4x^2-12x-12x+36-98=0
We add all the numbers together, and all the variables
4x^2-24x-62=0
a = 4; b = -24; c = -62;
Δ = b2-4ac
Δ = -242-4·4·(-62)
Δ = 1568
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1568}=\sqrt{784*2}=\sqrt{784}*\sqrt{2}=28\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-28\sqrt{2}}{2*4}=\frac{24-28\sqrt{2}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+28\sqrt{2}}{2*4}=\frac{24+28\sqrt{2}}{8} $
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