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(2x-6)(5x+1)=0
We multiply parentheses ..
(+10x^2+2x-30x-6)=0
We get rid of parentheses
10x^2+2x-30x-6=0
We add all the numbers together, and all the variables
10x^2-28x-6=0
a = 10; b = -28; c = -6;
Δ = b2-4ac
Δ = -282-4·10·(-6)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-32}{2*10}=\frac{-4}{20} =-1/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+32}{2*10}=\frac{60}{20} =3 $
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