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(2x-6)(5x-7)=0
We multiply parentheses ..
(+10x^2-14x-30x+42)=0
We get rid of parentheses
10x^2-14x-30x+42=0
We add all the numbers together, and all the variables
10x^2-44x+42=0
a = 10; b = -44; c = +42;
Δ = b2-4ac
Δ = -442-4·10·42
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-16}{2*10}=\frac{28}{20} =1+2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+16}{2*10}=\frac{60}{20} =3 $
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