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(2x-6)(6x+8)=0
We multiply parentheses ..
(+12x^2+16x-36x-48)=0
We get rid of parentheses
12x^2+16x-36x-48=0
We add all the numbers together, and all the variables
12x^2-20x-48=0
a = 12; b = -20; c = -48;
Δ = b2-4ac
Δ = -202-4·12·(-48)
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2704}=52$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-52}{2*12}=\frac{-32}{24} =-1+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+52}{2*12}=\frac{72}{24} =3 $
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