(2x-6)(6x+8)=0

Solution for (2x-6)(6x+8)=0 equation:

(2x-6)(6x+8)=0

We multiply parentheses ..

(+12x^2+16x-36x-48)=0

We get rid of parentheses

12x^2+16x-36x-48=0

We add all the numbers together, and all the variables

12x^2-20x-48=0

a = 12; b = -20; c = -48;
Δ = b2-4ac
Δ = -202-4·12·(-48)
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2704}=52$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-52}{2*12}=\frac{-32}{24}
=-1+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+52}{2*12}=\frac{72}{24}
=3
$