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(2x-6)(x+3)=180
We move all terms to the left:
(2x-6)(x+3)-(180)=0
We multiply parentheses ..
(+2x^2+6x-6x-18)-180=0
We get rid of parentheses
2x^2+6x-6x-18-180=0
We add all the numbers together, and all the variables
2x^2-198=0
a = 2; b = 0; c = -198;
Δ = b2-4ac
Δ = 02-4·2·(-198)
Δ = 1584
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1584}=\sqrt{144*11}=\sqrt{144}*\sqrt{11}=12\sqrt{11}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{11}}{2*2}=\frac{0-12\sqrt{11}}{4} =-\frac{12\sqrt{11}}{4} =-3\sqrt{11} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{11}}{2*2}=\frac{0+12\sqrt{11}}{4} =\frac{12\sqrt{11}}{4} =3\sqrt{11} $
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