(2x-6)+((x-5)/2)=16

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Solution for (2x-6)+((x-5)/2)=16 equation: 



(2x-6)+((x-5)/2)=16

We move all terms to the left:

(2x-6)+((x-5)/2)-(16)=0

We get rid of parentheses

2x+((x-5)/2)-6-16=0

We multiply all the terms by the denominator


2x*2)+((x-5)-6*2)-16*2)=0

We add all the numbers together, and all the variables

2x*2)+((x-5)=0

Wy multiply elements

4x^2=0

a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{8}=0$

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