(2x-6)+(x+42)+x=180

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Solution for (2x-6)+(x+42)+x=180 equation:



(2x-6)+(x+42)+x=180
We move all terms to the left:
(2x-6)+(x+42)+x-(180)=0
We add all the numbers together, and all the variables
x+(2x-6)+(x+42)-180=0
We get rid of parentheses
x+2x+x-6+42-180=0
We add all the numbers together, and all the variables
4x-144=0
We move all terms containing x to the left, all other terms to the right
4x=144
x=144/4
x=36

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