(2x-6)+21=(x+1)+30

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Solution for (2x-6)+21=(x+1)+30 equation: 



(2x-6)+21=(x+1)+30

We move all terms to the left:

(2x-6)+21-((x+1)+30)=0

We get rid of parentheses

2x-((x+1)+30)-6+21=0



We calculate terms in parentheses: -((x+1)+30), so:

(x+1)+30

We get rid of parentheses

x+1+30

We add all the numbers together, and all the variables

x+31

Back to the equation:

-(x+31)



We add all the numbers together, and all the variables

2x-(x+31)+15=0

We get rid of parentheses

2x-x-31+15=0

We add all the numbers together, and all the variables

x-16=0

We move all terms containing x to the left, all other terms to the right

x=16

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