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(2x-6)+x=120
We move all terms to the left:
(2x-6)+x-(120)=0
We add all the numbers together, and all the variables
x+(2x-6)-120=0
We get rid of parentheses
x+2x-6-120=0
We add all the numbers together, and all the variables
3x-126=0
We move all terms containing x to the left, all other terms to the right
3x=126
x=126/3
x=42
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